Subjective Type

Calculate the mass percent of $$O$$ present in sodium sulphate $$\displaystyle \left( { Na }_{ 2 }{ SO }_{ 4 } \right)$$.

Solution

The molar mass of sodium sulphate is $$\displaystyle 2(23)+32+4(16) = 46+32+64 = 142 \: g/mol $$

Mass percentage $$= \dfrac{\text{Mass of oxygen}}{\text{Mass of }Na_2SO_4}\times 100$$

The mass percentage of oxygen in sodium sulphate $$\displaystyle = \frac {64}{142} \times 100 = 45.07\%$$.

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