Single Choice

A magnetic moment of 1.73 BM will be shown by which one among the following?

A$$\left [ Cu(NH_{3})_{4} \right ]^{2+}$$
Correct Answer
B$$\left [ Ni(CN)_{4} \right ]^{2-}$$
C$$TiCl_{4}$$
D$$\left [ CoCl_{6} \right ]^{4-}$$

Solution

A magnetic moment of 1.73 BM will be shown by $$\left [ Cu(NH_{3})_{4} \right ]^{2+}$$.
Magnetic moment is given by the expression $$(\mu )=\sqrt{n(n+2)}$$
$$1.73=\sqrt{n(n+2)}$$
$$n=1$$
So, compound must contain one unpaired electron. The compound is $$[Cu(NH_{3})_{4}]^{2+}$$ as $$Cu^{2+}$$ has $$3d^9$$ electronic configuration.

SIMILAR QUESTIONS

Chemical Bonding

The magnetic moment of $$Co^{2+}$$ in square planar complex is:

Chemical Bonding

What are the spin-only magnetic moments (in BM) for Ni(II) ion in square-planar and octahedral geometry, respectively?

Chemical Bonding

Correct oder of magnetic moment of $$[Fe^{III}(CN)_6]^{3-}$$ ion and $$[Fe^(III) (H_2O)_6]^{3+}$$ ?

Chemical Bonding

In the manufacture of iron, a gas (A) is formed in the zone of combustion of the blast furnace. The gas (A) reacted with coke in the zone of fusion to form another gas (B). X moles of (B) reacts with iron at $$200^{o}$$C and 100 atm pressure to form a compound (C). The magnetic moment and effective atomic number of the C respectively are :

Chemical Bonding

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Chemical Bonding

The correct order of the calculated spin-only magnetic moments of complexes (A) to (D) is: (A) $$Ni{(CO)}_{4}$$ (B) $$[Ni{({H}_{2}O)}_{6}]{Cl}_{2}$$ (C) $${Na}_{2}[Ni{(CN)}_{4}]$$ (D) $$Pd{Cl}_{2}{(PP{h}_{3})}_{2}$$

Chemical Bonding

The correct order of the spin-only magnetic moments of the following complexes is : (I) $$[Cr(H_2O)_6]Br_2$$ (II) $$Na_4[Fe(CN)_6]$$ (III) $$Na_3[Fe(C_2O_4)_3]\ (\Delta_0 >P)$$ (IV) $$(Et_4N)_2[CoCl_4]$$

Chemical Bonding

The magnetic moment (spin only) of $$[\mathrm{N}\mathrm{i}\mathrm{C}l_{4}]^{2-}$$ is :

Chemical Bonding

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Chemical Bonding

The spin only magnetic moment value in Bohr magneton units of $$Cr(CO)_{6}$$ is :

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