Chemical Bonding
The magnetic moment of $$Co^{2+}$$ in square planar complex is:
$$\begin{matrix}Na_2S&+&X&\longrightarrow& Na_2[Fe(CN)_5(NOS)]\\&&&&purple\:color\end{matrix}$$ Find the value of magnetic moment of X.
With sodium nitrprusside solution, ionic sulphide gives a purple colour in alkaline medium.
$$Na_2S + Na_2[Fe(CN)_5NO] \longrightarrow Na_4[Fe(CN)_5NOS]$$
$$Purple\ colour$$
Here X is,
$$Na_2[Fe(CN)_5(NO)]$$
+2 +1
$$\Rightarrow Fe^{+2} = d^6$$ , due to strong ligand pairing happens and low spin complex forms as shown in the figure.
So, it have zero unpaired electron and zero magnetic moment.
Hence, the correct option is A.
The magnetic moment of $$Co^{2+}$$ in square planar complex is:
What are the spin-only magnetic moments (in BM) for Ni(II) ion in square-planar and octahedral geometry, respectively?
Correct oder of magnetic moment of $$[Fe^{III}(CN)_6]^{3-}$$ ion and $$[Fe^(III) (H_2O)_6]^{3+}$$ ?
In the manufacture of iron, a gas (A) is formed in the zone of combustion of the blast furnace. The gas (A) reacted with coke in the zone of fusion to form another gas (B). X moles of (B) reacts with iron at $$200^{o}$$C and 100 atm pressure to form a compound (C). The magnetic moment and effective atomic number of the C respectively are :
The correct order of the calculated spin-only magnetic moments of complexes (A) to (D) is: (A) $$Ni{(CO)}_{4}$$ (B) $$[Ni{({H}_{2}O)}_{6}]{Cl}_{2}$$ (C) $${Na}_{2}[Ni{(CN)}_{4}]$$ (D) $$Pd{Cl}_{2}{(PP{h}_{3})}_{2}$$
The correct order of the spin-only magnetic moments of the following complexes is : (I) $$[Cr(H_2O)_6]Br_2$$ (II) $$Na_4[Fe(CN)_6]$$ (III) $$Na_3[Fe(C_2O_4)_3]\ (\Delta_0 >P)$$ (IV) $$(Et_4N)_2[CoCl_4]$$
The magnetic moment (spin only) of $$[\mathrm{N}\mathrm{i}\mathrm{C}l_{4}]^{2-}$$ is :
A magnetic moment of 1.73 BM will be shown by which one among the following?
The complex showing a spin-only magnetic moment of $$2.82\ B.M$$. is:
The spin only magnetic moment value in Bohr magneton units of $$Cr(CO)_{6}$$ is :