Single Choice

The spin only magnetic moment value in Bohr magneton units of $$Cr(CO)_{6}$$ is :

A$$0$$
Correct Answer
B$$2.84$$
C$$4.90$$
D$$5.92$$

Solution

In $$Cr(CO)_6$$, Cr is in 0 oxidation state and have
electronic configuration = $$3d^5 4s^1$$
but due to the presence of strong field ligand (CO), pairing of elctrons takes place,
and unpaired electrons become zero,
hence, spin only magnetic moment value becomes zero.


SIMILAR QUESTIONS

Chemical Bonding

The magnetic moment of $$Co^{2+}$$ in square planar complex is:

Chemical Bonding

What are the spin-only magnetic moments (in BM) for Ni(II) ion in square-planar and octahedral geometry, respectively?

Chemical Bonding

Correct oder of magnetic moment of $$[Fe^{III}(CN)_6]^{3-}$$ ion and $$[Fe^(III) (H_2O)_6]^{3+}$$ ?

Chemical Bonding

In the manufacture of iron, a gas (A) is formed in the zone of combustion of the blast furnace. The gas (A) reacted with coke in the zone of fusion to form another gas (B). X moles of (B) reacts with iron at $$200^{o}$$C and 100 atm pressure to form a compound (C). The magnetic moment and effective atomic number of the C respectively are :

Chemical Bonding

$$\begin{matrix}Na_2S&+&X&\longrightarrow& Na_2[Fe(CN)_5(NOS)]\\&&&&purple\:color\end{matrix}$$ Find the value of magnetic moment of X.

Chemical Bonding

The correct order of the calculated spin-only magnetic moments of complexes (A) to (D) is: (A) $$Ni{(CO)}_{4}$$ (B) $$[Ni{({H}_{2}O)}_{6}]{Cl}_{2}$$ (C) $${Na}_{2}[Ni{(CN)}_{4}]$$ (D) $$Pd{Cl}_{2}{(PP{h}_{3})}_{2}$$

Chemical Bonding

The correct order of the spin-only magnetic moments of the following complexes is : (I) $$[Cr(H_2O)_6]Br_2$$ (II) $$Na_4[Fe(CN)_6]$$ (III) $$Na_3[Fe(C_2O_4)_3]\ (\Delta_0 >P)$$ (IV) $$(Et_4N)_2[CoCl_4]$$

Chemical Bonding

The magnetic moment (spin only) of $$[\mathrm{N}\mathrm{i}\mathrm{C}l_{4}]^{2-}$$ is :

Chemical Bonding

A magnetic moment of 1.73 BM will be shown by which one among the following?

Chemical Bonding

The complex showing a spin-only magnetic moment of $$2.82\ B.M$$. is:

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