Subjective Type

A metal ion $$M^{n+}$$ having $$d^4$$ valence electronic configuration combines with three bidentate ligands to form a compound. Assuming $$\Delta_0 > P$$: Explain orbital splitting during this complex formation.

Solution

As $$\Delta_0 > P$$ pairing will occur in the $$t_{2g}$$ orbitals and $$e_g$$ orbitals will remains vacant.

SIMILAR QUESTIONS

Coordination Compounds

The extent of crystal field splitting in octahedral complex of the given metal with particular weak field ligand are such that :

Coordination Compounds

Define crystal field splitting energy.

Coordination Compounds

On the basis of crystal field theory, write the electronic configuration for $$d^{4}$$ ion, if $$\Delta_0 > P$$

Coordination Compounds

The complex that has the highest crystal splitting energy $$(\Delta)$$, is:

Coordination Compounds

Geometrical shapes of the complexes formed by the reaction of $$Ni^{2+}$$ with $$Cl^{-},\ CN^{-}$$ and $$H_{2}O$$, respectively, are:

Coordination Compounds

Geometrical shapes of the complexes formed by the reaction of $$Ni^{2+}$$ with $$Cl^{-},\ CN^{-}$$ and $$H_{2}O$$, respectively, are:

Coordination Compounds

Select the correct order of magnetic moment (in B.M.) from the following options :

Coordination Compounds

The increasing order of the crystal field splitting power of some common ligands is?

Coordination Compounds

In which of the following complexes of the Co (atomic no. $$=27$$), will the magnitude of $$\Delta_o$$ be the highest?

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