Single Choice

Select the correct order of magnetic moment (in B.M.) from the following options :

A$$[MnCl_4]^{2-} > \ [CoCl_4]^{2-} > \ [Fe(CN)_6]^{4-}$$
Correct Answer
B$$[Fe(CN)_6]^{4-} > \ [MnCl_4]^{2-} > \ [CoCl_4]^{2-}$$
C$$[Fe(CN)_6]^{4-} > \ [CoCl_4]^{2-} > \ [MnCl_4]^{2-}$$
D$$[MnCl_4]^{2-} > \ [Fe(CN)_6]^{4-} > \ [CoCl_4]^{2-} $$

Solution

The correct order of magnetic moment (in B.M.) is $$[MnCl_4]^{2-} > \ [CoCl_4]^{2-} > \ [Fe(CN)_6]^{4-}$$

$$[MnCl_4]^{2-}$$ has $$3d^{5}$$ orbitals and 5 unpaired electron.

$$[CoCl_4]^{2-}$$ has $$3d^{7}$$ orbitals and 3 unpaired electron.

$$[Fe(CN)_6]^{4-}$$ has $$3d^{6}$$ orbitals and 0 unpaired electrons.

More the number of unpaired electrons more is the magnetic moment.

Option (A) is correct.

SIMILAR QUESTIONS

Coordination Compounds

The extent of crystal field splitting in octahedral complex of the given metal with particular weak field ligand are such that :

Coordination Compounds

Define crystal field splitting energy.

Coordination Compounds

On the basis of crystal field theory, write the electronic configuration for $$d^{4}$$ ion, if $$\Delta_0 > P$$

Coordination Compounds

The complex that has the highest crystal splitting energy $$(\Delta)$$, is:

Coordination Compounds

Geometrical shapes of the complexes formed by the reaction of $$Ni^{2+}$$ with $$Cl^{-},\ CN^{-}$$ and $$H_{2}O$$, respectively, are:

Coordination Compounds

A metal ion $$M^{n+}$$ having $$d^4$$ valence electronic configuration combines with three bidentate ligands to form a compound. Assuming $$\Delta_0 > P$$: Explain orbital splitting during this complex formation.

Coordination Compounds

Geometrical shapes of the complexes formed by the reaction of $$Ni^{2+}$$ with $$Cl^{-},\ CN^{-}$$ and $$H_{2}O$$, respectively, are:

Coordination Compounds

The increasing order of the crystal field splitting power of some common ligands is?

Coordination Compounds

In which of the following complexes of the Co (atomic no. $$=27$$), will the magnitude of $$\Delta_o$$ be the highest?

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