Organic Chemistry
In organic compounds, Sulphur is estimated as:
A red solution is obtained when ferric chloride solution is added to sodium extract. It indicates both nitrogen and sulphur are present in the organic compound.
Ferric Chloride $$(FeCl_{3})$$ that reacts with Sodium Thiocyanate $$(NaCNS)$$ to form Ferric Thiocyanate $$[Fe(CNS)_{3}]$$ which is blood red in color. This test can be used as a confirmatory test for organic compounds containing both Nitrogen and Sulfur (e.g. Methionine amino acid).
$$NaCN+S_{8} \overset{\Delta }{\rightarrow }\underset{\mathit{Sodium\ Thiocynate}}{NaSCN}$$
$$Fe^{+3}+3NaSCN \rightarrow \underset{\ \ Ferric\ thiocynate\\ \\ (Blood\ red\ colouration)}{Fe(SCN)_{3}}$$
$$\mathbf{Hence\ the\ correct\ answer\ is\ the\ option \ (A)}$$
In organic compounds, Sulphur is estimated as:
In an estimation of S by Carius method 0.2175g of the compound gave 0.5825g of $$BaSO_{4}$$. Percentage of S is :
0.32g of organic compound in Carius method gave 0.233g of $$ BaSO_{4}$$. The percentage of $$S$$ in the organic compound is:
An organic compound containing sulphur is estimated by Carius method in which fuming $$HNO_3$$ is used to convert S into :
Fill in the blanks : In Carius method for sulphur and phosphorus, sulphur is estimated as ............. and phophorus is estimated as ..............
In the estimation of sulphur, organic compound on treating with conc. $$HNO_3$$ is converted to
How much sulphur is present in organic compound if on analysis $$0.53\ gm$$ of this compound gives $$1.158\ gm$$ of $$BaSO_{4}$$?
In Carius method for the quantitative estimation of sulphur. it is estimated by__________.
The violet colour obtained during the test of sulphur by Lassaigne's test is due to the formation of:
Sulphur is estimated by carius method as barium sulphate.