Organic Chemistry
In organic compounds, Sulphur is estimated as:
In Carius method for the quantitative estimation of sulphur. it is estimated by__________.
Sulphur present in any organic compound is also estimated by Carius method.
Sulphur present in any organic compound is oxidized to sulphuric acid by digesting with fuming nitric acid. Sulphuric acid so formed is then quantitatively precipitated as barium sulphate by the addition of excess barium chloride. The precipitate of barium sulphate is filtered, washed, dried and weighed.
In organic compounds, Sulphur is estimated as:
In an estimation of S by Carius method 0.2175g of the compound gave 0.5825g of $$BaSO_{4}$$. Percentage of S is :
0.32g of organic compound in Carius method gave 0.233g of $$ BaSO_{4}$$. The percentage of $$S$$ in the organic compound is:
An organic compound containing sulphur is estimated by Carius method in which fuming $$HNO_3$$ is used to convert S into :
Fill in the blanks : In Carius method for sulphur and phosphorus, sulphur is estimated as ............. and phophorus is estimated as ..............
In the estimation of sulphur, organic compound on treating with conc. $$HNO_3$$ is converted to
How much sulphur is present in organic compound if on analysis $$0.53\ gm$$ of this compound gives $$1.158\ gm$$ of $$BaSO_{4}$$?
The violet colour obtained during the test of sulphur by Lassaigne's test is due to the formation of:
Sulphur is estimated by carius method as barium sulphate.
A red solution is obtained when ferric chloride solution is added to sodium extract. It indicates both nitrogen and sulphur are present in the organic compound.