Single Choice

A student performs a titration with different burettes and finds titre values of $$25.2$$ ml, $$25.25$$ ml and $$25.0$$ ml. The number of significant figures in the average titre value is :

A$$3$$
Correct Answer
B$$4$$
C$$6$$
D$$8$$

Solution

We have $$25.20, 25.25$$ and $$25.00$$ ml.

Average= $$\displaystyle \frac{25.20+25.25+25.00}{3}$$
= $$\displaystyle \frac{75.45}{3}$$

= $$25.15 = 25.1$$

In case of division, the final answer will contain as many significant figures as there are in an number with least significant numbers.

So, the significant number is $$3$$.

SIMILAR QUESTIONS

Hydrocarbons

The major product of the following reaction is: $${CH}_{3}C\equiv CH\xrightarrow [ (ii)\ DI ]{ (i)\ DCl \ (1\ equiv) } $$

Hydrocarbons

The synthesis of $$3-octyne$$ is achieved by adding a bromoalkane into a mixture of sodium amide and an alkyne. The bromoalkane and alkyne respectively are:

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Ethylidene chloride can be prepared by the reaction of $$HCl$$ and:

Hydrocarbons

Which of the following would be produced when acetylene reacts with $$HCl$$?

Hydrocarbons

$$CH\equiv CH\xrightarrow [Excess]{HCl}A\xrightarrow [\Delta]{Hydrolysis} B \xrightarrow [Na-Hg/H_2O]{Reduction}C$$ Compound $$C$$ is:

Hydrocarbons

The end product (C) of the above sequence of reaction is:

Hydrocarbons

The gases (B), (C) and (D), respectively, are:

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