Single Choice

$$CH\equiv CH\xrightarrow [Excess]{HCl}A\xrightarrow [\Delta]{Hydrolysis} B \xrightarrow [Na-Hg/H_2O]{Reduction}C$$ Compound $$C$$ is:

Aethanal
Bpropanal
Cethanol
Correct Answer
D2-methyl butan-1-ol

Solution

Acetylene on treatment with excess HCl gives 1,1-dichloroethane. Two molecules of HCl add to carbon carbon triple bond. Both Cl atom is added to same C atom. 1,1-dichloroethane on hydrolysis gives ethane-1,1-diol. On heating, ethane-1,1-diol loses a molecule of water to form acetaldehyde. Acetaldehyde on reduction with sodium amalgam gives ethanol which is compound C.

SIMILAR QUESTIONS

Hydrocarbons

The major product of the following reaction is: $${CH}_{3}C\equiv CH\xrightarrow [ (ii)\ DI ]{ (i)\ DCl \ (1\ equiv) } $$

Hydrocarbons

The synthesis of $$3-octyne$$ is achieved by adding a bromoalkane into a mixture of sodium amide and an alkyne. The bromoalkane and alkyne respectively are:

Hydrocarbons

A student performs a titration with different burettes and finds titre values of $$25.2$$ ml, $$25.25$$ ml and $$25.0$$ ml. The number of significant figures in the average titre value is :

Hydrocarbons

Ethylidene chloride can be prepared by the reaction of $$HCl$$ and:

Hydrocarbons

Which of the following would be produced when acetylene reacts with $$HCl$$?

Hydrocarbons

The end product (C) of the above sequence of reaction is:

Hydrocarbons

The gases (B), (C) and (D), respectively, are:

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