Single Choice

The synthesis of $$3-octyne$$ is achieved by adding a bromoalkane into a mixture of sodium amide and an alkyne. The bromoalkane and alkyne respectively are:

A$$BrCH_{2}CH_{2}CH_{2}CH_{3}$$ and $$CH_{3}CH_{2}C\equiv CH$$
B$$BrCH_{2}CH_{2}CH_{3}$$ and $$CH_{3}CH_{2}CH_{2}C \equiv CH$$
C$$BrCH_{2}CH_{2}CH_{2}CH_{2}CH_{3}$$ and $$CH_{3}C\equiv CH$$
D$$BrCH_{2}CH_{2}CH_{2}CH_{3}$$ and $$CH_{3}CH_{2}C\equiv CH$$
Correct Answer

Solution


$$A$$ will give 3-nonyne.

$$B$$ will give 4-octyne.

$$C$$ will give 2-octyne.

$$D$$ will give 3-octyne.

Hence, the correct answer is $$D$$.


SIMILAR QUESTIONS

Hydrocarbons

The major product of the following reaction is: $${CH}_{3}C\equiv CH\xrightarrow [ (ii)\ DI ]{ (i)\ DCl \ (1\ equiv) } $$

Hydrocarbons

A student performs a titration with different burettes and finds titre values of $$25.2$$ ml, $$25.25$$ ml and $$25.0$$ ml. The number of significant figures in the average titre value is :

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Ethylidene chloride can be prepared by the reaction of $$HCl$$ and:

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Which of the following would be produced when acetylene reacts with $$HCl$$?

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$$CH\equiv CH\xrightarrow [Excess]{HCl}A\xrightarrow [\Delta]{Hydrolysis} B \xrightarrow [Na-Hg/H_2O]{Reduction}C$$ Compound $$C$$ is:

Hydrocarbons

The end product (C) of the above sequence of reaction is:

Hydrocarbons

The gases (B), (C) and (D), respectively, are:

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