Commercial Mathematics
Find the amount and the compound interest on ₹ 2500 for 2 years at 10% per annum, compounded annually.
Abhay borrowed $$₹\ 16000$$ at $$7 \dfrac{1}{2} \%$$ per annum simple interest. On the same day, he lent it to gurmeet at the same rate but compounded annually. What does he gain at the end of $$2$$ years?
Given:
Present value $$= ₹ 16000$$
Interest rate $$= 7\dfrac{1}{2} \% per annum $$= 15/2 \%$$
Time $$=2$$ years
To find the amount we have the formula,
Amount $$(A) = P (1+(r/100))^n$$
where $$P$$ is the present value, $$r$$ is the rate of interest, $$n$$ is time in years.
Now substituting the values in above formula we get,
$$\therefore A = 16000 (1 +(15/2)/100)^2$$
$$\Rightarrow A = 16000 (1+3/40)^2$$
$$\Rightarrow A =16000 (43/40)^2$$
$$\Rightarrow A = 16000 (1894/1600)$$
$$\Rightarrow A = ₹\ 18490$$
Now, we find the compound interest,
∴ Compound interest $$= A – P$$
$$= 18490 – 16000 = ₹\ 2490$$
Now we find the simple interest,
Simple interest $$(SI) = PTR/100$$
where $$P$$ is principle amount, $$T$$ is time taken, $$R$$ is rate per annum
$$SI = (16000 × (15/2) × 2) / 100$$
$$= 160 × 15$$
$$= ₹\ 2400$$
Abhay's gain at the end of $$2$$ years$$ = (CI – SI)$$
$$= 2490 – 2400$$
$$= ₹\ 90$$
Find the amount and the compound interest on ₹ 2500 for 2 years at 10% per annum, compounded annually.
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A person invests 10000 for two years at a certain rate of interest, compounded annually. At the end of one year this sum amounts to 11200. Calculate: (i) the rate of interest per annum. (ii) the amount at the end of second year.