Subjective Type

Find the amount and compound interest on $$₹\ 9000$$ for $$2$$ years $$4$$ months at $$10 \%$$ per annum compounded annually.

Solution

Given:

Present value $$= ₹\ 9000$$

Interest rate $$= 10 \%$$ per annum

Time $$=2$$ years $$4$$ months = $$(2 + \dfrac{1}{3})$$ years= $$7/3$$ years


To find the amount we have the formula,

Amount $$(A) = P (1+(r/100))^n$$
where $$P$$ is the present value, $$r$$ is the rate of interest and $$n$$ is time in years.

Now substituting the values in above formula we get,

$$\therefore A = 9000 (1 +10/100)^2 [1 + (1/3 × 10)/100] $$

$$\Rightarrow A = 9000 (1+1/10)^2 (1+1/30) $$

$$\Rightarrow A = 9000 (11/10)^2 (31/30)$$

$$\Rightarrow A = 9000 × 121/100 × 31/30 = 9 × 121× 31/3$$

$$\Rightarrow A = ₹\ 11253$$

And Compound interest $$= A – P$$

$$= 11253 – 6000 = ₹\ 2253$$


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