Solution

Given:

Present value $$= ₹\ 10000$$

Interest rate $$= 12 \%$$ per annum

Time $$= 1\dfrac{1}{2}$$ years $$=3/2$$ years

To find the amount we have the formula,
Amount $$(A) = P (1+(r/100))^n$$

where $$P$$ is present value, $$r$$ is rate of interest, $$n$$ is time in years

Now substituting the values in above formula we get,

$$\therefore A = 10000 (1 +12/100)^1 [1 + (12/2 )/100] $$

$$\Rightarrow A = 10000(1+12/100)^ 1(1+6/100) $$

$$\Rightarrow A = 10000 (112/100) (106/100)$$
$$\Rightarrow A = 1 × 112 × 106$$

$$\Rightarrow A = ₹\ 11872$$

∴ Compound interest $$= A – P$$

$$= 11872 – 10000= ₹\ 1872$$