Atomic Structure
What is the maximum number of orbitals that can be identified with the following quantum numbers? $$n=3,l=+1, m_l=0$$
An electron is in one of the 3d orbitals. Give the possible values of n, l and $$\displaystyle { m }_{ l }$$ for this electron.
For an electron in 3d orbital, the possible values of the quantum numbers are $$n=3$$, $$l=2$$, $$ml=-2,-1,0,+1,+2$$
What is the maximum number of orbitals that can be identified with the following quantum numbers? $$n=3,l=+1, m_l=0$$
The number of orbitals associated with quantum numbers $$n=5,m_s=+\dfrac{1}{2}$$ is :
The quantum number of four electrons are given below- $$I. n=4,l=2, m_l=-2, m_s=-1/2$$ $$II. n=3,l=2, m_l=1, m_s=+1/2$$ $$III. n=4,l=1, m_l=0, m_s=+1/2$$ $$IV. n=3,l=1, m_l=1, m_s=-1/2$$ The correct order of their increasing energy will be:
The total number of orbitals associated with the principal quantum number 5 is :
Which one is a wrong statement?
What is the maximum number of orbitals that can be identified with the following quantum number? $$n = 3, l = 1, m = 0$$
The maximum number of electrons that can have principal quantum number, $$n =3$$ , and spin quantum number, $$m_{s}=-1/2$$, is:
The electrons identified by quantum numbers $$n$$ and $$l$$ can be placed in the order of increasing energy as: 1. $$n=4, l=1$$ 2. $$n=4, l=0$$ 3. $$n=3, l=2$$ 4. $$n=3, l=1$$
The correct set of quantum numbers for valence electron of $$Rb$$ (atomic number 37) is:
What is the lowest value of n that allows g orbitals to exist?