Single Choice

The number of orbitals associated with quantum numbers $$n=5,m_s=+\dfrac{1}{2}$$ is :

A$$11$$
B$$25$$
Correct Answer
C$$50$$
D$$15$$

Solution

$$n=5 $$ (Principal quantum numbers) $$\therefore$$ Subshall $$\Rightarrow s,p,d,f,g$$ Since $$m_s=+\dfrac{1}{2}$$ (clockwise) Refer image. $$\therefore$$ Total no. of orbital $$=1+3+5+7+9$$ $$=25$$ orbitals Hence, option $$B$$ is correct.

SIMILAR QUESTIONS

Atomic Structure

What is the maximum number of orbitals that can be identified with the following quantum numbers? $$n=3,l=+1, m_l=0$$

Atomic Structure

The quantum number of four electrons are given below- $$I. n=4,l=2, m_l=-2, m_s=-1/2$$ $$II. n=3,l=2, m_l=1, m_s=+1/2$$ $$III. n=4,l=1, m_l=0, m_s=+1/2$$ $$IV. n=3,l=1, m_l=1, m_s=-1/2$$ The correct order of their increasing energy will be:

Atomic Structure

The total number of orbitals associated with the principal quantum number 5 is :

Atomic Structure

What is the maximum number of orbitals that can be identified with the following quantum number? $$n = 3, l = 1, m = 0$$

Atomic Structure

The maximum number of electrons that can have principal quantum number, $$n =3$$ , and spin quantum number, $$m_{s}=-1/2$$, is:

Atomic Structure

The electrons identified by quantum numbers $$n$$ and $$l$$ can be placed in the order of increasing energy as: 1. $$n=4, l=1$$ 2. $$n=4, l=0$$ 3. $$n=3, l=2$$ 4. $$n=3, l=1$$

Atomic Structure

The correct set of quantum numbers for valence electron of $$Rb$$ (atomic number 37) is:

Atomic Structure

What is the lowest value of n that allows g orbitals to exist?

Atomic Structure

An electron is in one of the 3d orbitals. Give the possible values of n, l and $$\displaystyle { m }_{ l }$$ for this electron.

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