Atomic Structure
What is the maximum number of orbitals that can be identified with the following quantum numbers? $$n=3,l=+1, m_l=0$$
Which one is a wrong statement?
The statement (A) is incorrect. The spin of electron in $$2p_Z$$ orbital should be same as that of $$2p_x$$ or $$2p_y$$ electron.
The stabilizing effect arises whenever two or more electrons with the same spin are present in the degenerate orbitals of a subshell. These electrons have tendency to exchange their position and energy released due to this exchange is called exchange energy.
What is the maximum number of orbitals that can be identified with the following quantum numbers? $$n=3,l=+1, m_l=0$$
The number of orbitals associated with quantum numbers $$n=5,m_s=+\dfrac{1}{2}$$ is :
The quantum number of four electrons are given below- $$I. n=4,l=2, m_l=-2, m_s=-1/2$$ $$II. n=3,l=2, m_l=1, m_s=+1/2$$ $$III. n=4,l=1, m_l=0, m_s=+1/2$$ $$IV. n=3,l=1, m_l=1, m_s=-1/2$$ The correct order of their increasing energy will be:
The total number of orbitals associated with the principal quantum number 5 is :
What is the maximum number of orbitals that can be identified with the following quantum number? $$n = 3, l = 1, m = 0$$
The maximum number of electrons that can have principal quantum number, $$n =3$$ , and spin quantum number, $$m_{s}=-1/2$$, is:
The electrons identified by quantum numbers $$n$$ and $$l$$ can be placed in the order of increasing energy as: 1. $$n=4, l=1$$ 2. $$n=4, l=0$$ 3. $$n=3, l=2$$ 4. $$n=3, l=1$$
The correct set of quantum numbers for valence electron of $$Rb$$ (atomic number 37) is:
What is the lowest value of n that allows g orbitals to exist?
An electron is in one of the 3d orbitals. Give the possible values of n, l and $$\displaystyle { m }_{ l }$$ for this electron.