Single Choice

Chloro compound of vanadium has only spin magnetic moment of $$1.73\ BM$$. This vanadium chloride has the formula: [Atomic number of $$V=23$$]

A$$VCl_2$$
B$$VCl_4$$
Correct Answer
C$$VCl_3$$
D$$VCl_5$$

Solution

Magnetic moment $$=\sqrt{n(n+2)}$$
where $$n = $$ number of unpaired electrons

$$\sqrt{n(n+2)}=1.73$$

$$\therefore n=1$$
Electronic configuration of $$V$$ is $$[Ar]4s^23d^3$$. For only one unpaired electron it has to be $$V^{4+}$$.

Hence, the formula of vanadium chloride is $$VCl_4$$.

Therefore, the correct option is $$B$$.

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