Single Choice

The paramagnatic property of the oxygen molecule due to the presence of unpaired electrons present in:

A$$(\sigma 2p_x)^1$$ and $$(\sigma^*2p_x)^1$$
B$$(\sigma 2p_x)^1$$ and $$(\pi 2p_y)^1$$
C$$(\pi^* 2p_y)^1$$ and $$(\pi^*2p_x)^1$$
Correct Answer
D$$(\pi^* 2p_y)^1$$ and $$(\pi2p_y)^1$$

Solution



The paramagnetic property in oxygen came through unpaired electron which can be explained which can be explained by molecular orbital theory.


SIMILAR QUESTIONS

Chemical Bonding

Odd electron bond is present in:

Chemical Bonding

Which is paramagnetic and coloured?

Chemical Bonding

What is the magnetic moment of $$[FeF_6]^{3-}$$?

Chemical Bonding

If the magnetic moment of a dioxygen species is 1.73 BM, it may be:

Chemical Bonding

Chloro compound of vanadium has only spin magnetic moment of $$1.73\ BM$$. This vanadium chloride has the formula: [Atomic number of $$V=23$$]

Chemical Bonding

Which one of the following molecules is paramagnetic?

Chemical Bonding

Which of the following species is not paramagnetic ?

Chemical Bonding

Which one of the following property is not shown by $$NO$$?

Chemical Bonding

Magnetic moment $$2.84\ BM$$ is given by : (Atomic numbers : $$Ni=28, Ti=22, Cr=24, Co=27)$$

Chemical Bonding

The pair(s) of reagents that yield paramagnetic species is/are:

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