Subjective Type

$$[Fe(CN)_6]^{-3}$$ is low spin complex but $$[Fe(H_2O)_6]^{+3}$$ is high spin complex. Explain.

Solution

According to spectrochemical series, $${CN}^{-}$$ is a strong field ligand and can pair electrons while $${H}_{2}O$$ is a weak field ligand and thus cannot pair electron.
Hence due to presence of unpaired electrons, $${\left[ Fe {\left( {H}_{2}O \right)}_{6} \right]}^{+3}$$ is a high spin complex while $${\left[ Fe{\left( CN \right)}_{6} \right]}^{-3}$$ is a low spin complex.

SIMILAR QUESTIONS

Coordination Compounds

Which of the following is paramagnetic?

Coordination Compounds

$$2.76 g$$ of silver carbonate on being strongly heated yields a residue weighing:

Coordination Compounds

Which of theses statements about $$[Co(CN)_6]^{3-}$$ is true?

Coordination Compounds

The correct statement about the magnetic properties of $$[Fe(CN)_6]^{3-}$$ and $$[FeF_6]^{3-}$$ is $$(Z=26)$$:

Coordination Compounds

Three complexes, $$[CoCl(NH_3)_5]^{2+} (I)$$, $$[Co(NH_3)_5H_2O]^{3+} (II)$$ and $$[Co(NH_3)_6]^{3+}(III)$$ absorb light in the visible region. The correct order of the wavelength of light absorbed by them is:

Coordination Compounds

Which of the following facts about the complex $$[{C}{r}({N}{H}_3)_{6}]{C}l_{3}$$ is wrong?

Coordination Compounds

Which of the following will form an octahedral complex?

Coordination Compounds

For the octahedral complexes of $$\displaystyle Fe^{3+}$$ in $$\displaystyle SCN^{-}$$ (thiocyanato-$$S$$) and in $$\displaystyle CN^{-}$$ ligand environments, the difference between the spin-only magnetic moments in Bohr magnetons (when approximated to the nearest integer) is: [Atomic number of Fe = 26]

Coordination Compounds

The correct statement(s) regarding the binary transition metal carbonyl compounds is/are: (Atomic numbers: $$Fe=26$$, $$Ni=28$$).

Coordination Compounds

Low spin tetrahedral complexes are not formed because:

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