Single Choice

Which of the following facts about the complex $$[{C}{r}({N}{H}_3)_{6}]{C}l_{3}$$ is wrong?

AThe complex involves $${d}^{2}{s}{p}^{3}$$ hybridisation and is octahedral in shape.
BThe complex is paramagnetic.
CThe complex is an outer orbital complex.
Correct Answer
DThe complex gives white precipitate with silver nitrate solution.

Solution

The complex $$[Cr(NH_3)-6] Cl_3$$ involved $$d^2sp^3$$ hybridization as it involves $$(n-1)d$$ orbitals for hybridization. It is an inner orbital complex.

The d-orbital involved in hybridization belongs to the penultimate shell due to the presence of strong ligand.


SIMILAR QUESTIONS

Coordination Compounds

Which of the following is paramagnetic?

Coordination Compounds

$$2.76 g$$ of silver carbonate on being strongly heated yields a residue weighing:

Coordination Compounds

Which of theses statements about $$[Co(CN)_6]^{3-}$$ is true?

Coordination Compounds

$$[Fe(CN)_6]^{-3}$$ is low spin complex but $$[Fe(H_2O)_6]^{+3}$$ is high spin complex. Explain.

Coordination Compounds

The correct statement about the magnetic properties of $$[Fe(CN)_6]^{3-}$$ and $$[FeF_6]^{3-}$$ is $$(Z=26)$$:

Coordination Compounds

Three complexes, $$[CoCl(NH_3)_5]^{2+} (I)$$, $$[Co(NH_3)_5H_2O]^{3+} (II)$$ and $$[Co(NH_3)_6]^{3+}(III)$$ absorb light in the visible region. The correct order of the wavelength of light absorbed by them is:

Coordination Compounds

Which of the following will form an octahedral complex?

Coordination Compounds

For the octahedral complexes of $$\displaystyle Fe^{3+}$$ in $$\displaystyle SCN^{-}$$ (thiocyanato-$$S$$) and in $$\displaystyle CN^{-}$$ ligand environments, the difference between the spin-only magnetic moments in Bohr magnetons (when approximated to the nearest integer) is: [Atomic number of Fe = 26]

Coordination Compounds

The correct statement(s) regarding the binary transition metal carbonyl compounds is/are: (Atomic numbers: $$Fe=26$$, $$Ni=28$$).

Coordination Compounds

Low spin tetrahedral complexes are not formed because:

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