Single Choice

For $$Na^+, Mg^{2+}, F^-$$ and $$O^{2-}$$ the correct order of increasing ionic radii is :

A$$O^{2-} < F^- < Na^+ < Mg^{2+}$$
B$$Mg^{2+} < Na^+ < F^- < O^{2-}$$
Correct Answer
C$$Mg^{2+} < O^{2-} < Na^{+} < F^-$$
D$$Na^+ < Mg^{2+} < F^- < O^{2-}$$

Solution

All the species are iso-electronic $$(10e^-)$$

For iso-electronic species more the positive change, smaller the ionic radii.

For iso-electronic species more negative change, bigger the ionic radii

Hence the order is $$Mg^{2+} < Na^+ < F^- < O^{2-}$$

Hence, the correct option is B.

SIMILAR QUESTIONS

Chemical Bonding

Which of the following will not exist in zwitter ionic form at pH$$=7$$?

Chemical Bonding

Which one of the following has largest ionic radius?

Chemical Bonding

Explain why cation are smaller and anions are larger in radii than their parent atoms?

Chemical Bonding

Which of the following is the correct order of size of the given species?

Chemical Bonding

If the ionic radii of $$k^{\displaystyle+}$$ and $$F^{\displaystyle-}$$ are nearly the same (i.e., $$1.34\:\mathring{A}$$), then the atomic radii of $$K$$ and $$F$$ respectively are:

Chemical Bonding

Consider the following statements: I. The radius of an anion is larger than that of parent atom. II. The I.E. increases from left to right in a period generally III. The electronegativity of an element is the tendency of an isolated atom to attract an electron. The correct statements are:

Chemical Bonding

The size of the species $$Pb, Pb^{2+}, and\ Pb^{4+}$$ decreases as:

Chemical Bonding

Which of the following has greater atomic size and why? $$y, y^{+1}, y^{-1}, y^{+2}, y^{-2}$$ Arrange them in ascending order of the atomic size.

Chemical Bonding

When a neutral atom is converted into cation, there is:

Contact Details