Chemical Bonding
For $$Na^+, Mg^{2+}, F^-$$ and $$O^{2-}$$ the correct order of increasing ionic radii is :
Which of the following is the correct order of size of the given species?
A cation is smaller and anion is larger in size than its parent atom.
$$I^-$$, $$I$$ and $$I^+$$ have 53 protons each. They have 54, 53 and 52 electrons respectively.
In $$I^-$$, fewer protons are acting on more electrons. Hence it has a larger size. In $$I^+$$, more protons are acting on fewer electrons. Hence it has a smaller size.
For $$Na^+, Mg^{2+}, F^-$$ and $$O^{2-}$$ the correct order of increasing ionic radii is :
Which of the following will not exist in zwitter ionic form at pH$$=7$$?
Which one of the following has largest ionic radius?
Which has the smallest size?
Explain why cation are smaller and anions are larger in radii than their parent atoms?
If the ionic radii of $$k^{\displaystyle+}$$ and $$F^{\displaystyle-}$$ are nearly the same (i.e., $$1.34\:\mathring{A}$$), then the atomic radii of $$K$$ and $$F$$ respectively are:
Consider the following statements: I. The radius of an anion is larger than that of parent atom. II. The I.E. increases from left to right in a period generally III. The electronegativity of an element is the tendency of an isolated atom to attract an electron. The correct statements are:
The size of the species $$Pb, Pb^{2+}, and\ Pb^{4+}$$ decreases as:
Which of the following has greater atomic size and why? $$y, y^{+1}, y^{-1}, y^{+2}, y^{-2}$$ Arrange them in ascending order of the atomic size.
When a neutral atom is converted into cation, there is: