Chemical Bonding
For $$Na^+, Mg^{2+}, F^-$$ and $$O^{2-}$$ the correct order of increasing ionic radii is :
Which of the following has greater atomic size and why? $$y, y^{+1}, y^{-1}, y^{+2}, y^{-2}$$ Arrange them in ascending order of the atomic size.
$$y^{-2}$$' has greater atomic size. Because here electrons are more than protons. The electrons exceed the influence of nuclear change and become free. This increases the size. Order of sizes is:
$$y^{+2} $$< $$y^{+1}$$< y < $$y^{-1} $$< $$y^{-2} $$.
Ascending order of atomic size is:
$$y^{+2} $$< $$y^{+1}$$<$$y$$ < $$y^{-1} $$< $$y^{-2} $$.
For $$Na^+, Mg^{2+}, F^-$$ and $$O^{2-}$$ the correct order of increasing ionic radii is :
Which of the following will not exist in zwitter ionic form at pH$$=7$$?
Which one of the following has largest ionic radius?
Which has the smallest size?
Explain why cation are smaller and anions are larger in radii than their parent atoms?
Which of the following is the correct order of size of the given species?
If the ionic radii of $$k^{\displaystyle+}$$ and $$F^{\displaystyle-}$$ are nearly the same (i.e., $$1.34\:\mathring{A}$$), then the atomic radii of $$K$$ and $$F$$ respectively are:
Consider the following statements: I. The radius of an anion is larger than that of parent atom. II. The I.E. increases from left to right in a period generally III. The electronegativity of an element is the tendency of an isolated atom to attract an electron. The correct statements are:
The size of the species $$Pb, Pb^{2+}, and\ Pb^{4+}$$ decreases as:
When a neutral atom is converted into cation, there is: