Single Choice

If the de-Broglie wavelength of a particle of mass $$m$$ is $$100$$ times its velocity then its value in terms of its mass $$(m)$$ and Planck's constant $$(h)$$ is:

A$$\dfrac {1}{10}\sqrt {\dfrac {m}{h}}$$
B$$10\sqrt {\dfrac {h}{m}}$$
Correct Answer
C$$\dfrac {1}{10}\sqrt {\dfrac {h}{m}}$$
D$$10\sqrt {\dfrac {m}{h}}$$

Solution

$$\lambda ={\dfrac {h}{mv}}$$

According to given question $$ \lambda = 100v $$

$$100v={\dfrac {h}{mv}}$$

so $$v^2=\dfrac{h}{100m}$$

$$ \lambda = 100v $$

$$ \lambda= 10 \sqrt {\dfrac{h}{ m}}$$

Hence, the correct option is $$B$$


SIMILAR QUESTIONS

Atomic Structure

The energy of a photon is $$3 \times 10^{-12}$$ ergs. Its wavelength (in nm) will be:

Atomic Structure

Calculate the de Broglie wavelength for a beam of electron whose energy is 100 eV:

Atomic Structure

Threshold wavelength of a metal is $${\lambda}_{0}$$. The de Broglie wavelength of photoelectron when the metal is irradiated with the radiation of wavelength $$\lambda$$ is:

Atomic Structure

The de Broglie wavelength associated with a ball of mass 200 g and moving at a speed of 5 meters / hour, is of the order of ($$h= 6.625\times 10^{-34}J s $$) is:

Atomic Structure

The de Broglie wavelength of a particle of mass 1 gram and velocity $$100\ { ms }^{ -1 }$$ is:

Atomic Structure

The de Broglie wavelength of an electron in the 4th Bohr orbit is:

Atomic Structure

The de Broglie wavelength (λ) associated with a photoelectron varies with the frequency (v) of the incident radiation as, [v0 is thrshold frequency]:

Atomic Structure

The de-Broglie's wavelength of electron present in first Bohr orbit of $$'H'$$ atom is?

Atomic Structure

Photoelectrons are liberated by ultraviolet light of wavelength $$3000\mathring{A}$$ from a metallic surface for which the photoelectric threshold is $$4000\mathring{A}$$. The de-Broglie wavelength of electrons emitted with maximum kinetic energy is:

Atomic Structure

The energy of an electron having de-Broglie wavelength $$'\lambda'$$ is: [h = Planck's constant, m = mass of electron]

Contact Details