Single Choice

The de Broglie wavelength (λ) associated with a photoelectron varies with the frequency (v) of the incident radiation as, [v0 is thrshold frequency]:

Aλ∝1(v−v0)32
Bλ∝1(v−v0)12
Correct Answer
Caλ∝1(v−v0)14
Dλ∝1(v−v0)

Solution

For electron

λDB=
λ
√
2mK.E.

(de broglie wavelength)

By photoelectric effect

hv=hv0+KE

λDB=
h
√
2m×(hv−hv0)



λDBα
1
(v−v0)
1
2



So, the correct option is B

SIMILAR QUESTIONS

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