Single Choice

The de Broglie wavelength associated with a ball of mass 200 g and moving at a speed of 5 meters / hour, is of the order of ($$h= 6.625\times 10^{-34}J s $$) is:

A$$10^{-15}m$$
B$$10^{-20}m$$
C$$10^{-25}m$$
D$$10^{-30}m$$
Correct Answer

Solution

According to de Broglie's equation
$$\lambda =\frac{h}{mv}$$
where, $$\lambda =$$ de-Broglie wavelength
$$h=6.626 \times 10^{−34}Js$$=Planck's constant
$$m=$$mass of object=200 g= 0.2 kg and $$v=$$ velocity$$= 5m/h=5/3600$$ m/s
upon substitution we get:
$$\lambda =\frac{6.626 \times 10^{−34}\times 3600}{0.2 \times 5}$$
$$\lambda=2.385 \times 10^{−30}$$m

SIMILAR QUESTIONS

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