d - block and f - block Elements
The magnetic moment of $$[Cu(NH_{3})_{4}]^{2+}$$ was found to be 1.73 B.M. The number of unpaired electrons in the complex is:
Select the correct order with respect to paramagnetic property of the ions.
The expression for magnetic moment is $$\sqrt{n(n+2)}$$, where $$n$$ is number of unpaired electrons. So, greater is the number of unpaired electrons, greater will be the magnetic moment of an ion. $$Mn^{+2}$$ has $$5$$ unpaired electrons. $$Cr^{+2}$$ has $$4$$ unpaired electrons. $$V^{+2}$$ has $$3$$ unpaired electrons. $$Ti^{+2}$$ has $$2$$ unpaired electrons. Hence, the correct order is as follows: $$Mn^{2+}>Cr^{2+}>V^{2+}>Ti^{2+}$$
The magnetic moment of $$[Cu(NH_{3})_{4}]^{2+}$$ was found to be 1.73 B.M. The number of unpaired electrons in the complex is:
Which of the following ions having the following electronic structure would have a maximum magnetic moment?
Titanium shows the magnetic moment of 1.73 B.M. in its compound. What is the oxidation number of $$Ti$$ in the compound?
The correct order of the spin-only magnetic moment of metal ions in the following low spin complexes, $$[V(CN)_6]^{4-}, [Fe(CN)_6]^{4-}$$, $$[Ru(NH_3)_6]^{3+}, $$ and $$[Cr(NH)_3)_6]^{2+}$$, is:
The calculated spin-only magnetic moments (BM) of the anionic and cationic species of $$[Fe(H_2O)_6]_2$$ and $$[Fe(CN)_6]$$, respectively, are:
Consider the hydrates ions of $$Ti^{2+}, V^{2+}, Ti^{3+}$$ and $$Sc^{3+}$$. The correct order of their spin-only magnetic moments is:
The INCORRECT statement is:
The correct order of spin-only magnetic moments among the following is: (Atomic number: $$Mn=25, Co=27, Ni=28, Zn=30)$$.
Which of the following transition metal ions will have definite value of magnetic moment?
Which of the following has the highest paramagnetism?