Single Choice

Select the correct order with respect to paramagnetic property of the ions.

A$$Mn^{2{+}} > Cr^{2+} > V^{2{+}} > Ti^{2+}$$
Correct Answer
B$$Ti^{2{+}} > V^{2{+}} > Mn^{2{+}} > Cr^{{2+}}$$
C$$V^{2{+}} > Ti^{2{+}} > Mn^{2{+}} > Cr^{2{+}}$$
D$$Ti^{3{+}} > V^{2{+}} > Mn^{2{+}} > Cr^{2{+}}$$

Solution

The expression for magnetic moment is $$\sqrt{n(n+2)}$$, where $$n$$ is number of unpaired electrons. So, greater is the number of unpaired electrons, greater will be the magnetic moment of an ion. $$Mn^{+2}$$ has $$5$$ unpaired electrons. $$Cr^{+2}$$ has $$4$$ unpaired electrons. $$V^{+2}$$ has $$3$$ unpaired electrons. $$Ti^{+2}$$ has $$2$$ unpaired electrons. Hence, the correct order is as follows: $$Mn^{2+}>Cr^{2+}>V^{2+}>Ti^{2+}$$


SIMILAR QUESTIONS

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