Single Choice

The correct order of spin-only magnetic moments among the following is: (Atomic number: $$Mn=25, Co=27, Ni=28, Zn=30)$$.

A$$[ZnCl_4]^{2-} > [NiCl_4]^{2-} > [CoCl_4]^{2-} > [MnCl_4]^{2-}$$
B$$[CoCl_4]^{2-} > [MnCl_4]^{2-} > [NiCl_4]^{2-} > [ZnCl_4]^{2-}$$
C$$[NiCl_4]^{2-} > [CoCl_4]^{2-} > [MnCl_4]^{2-} > [ZnCl_4]^{2-}$$
D$$[MnCl_4]^{2-} > [CoCl_4]^{2-} > [NiCl_4]^{2-} > [ZnCl_4]^{2-}$$
Correct Answer

Solution

The complex having higher number of unpaired electrons will have higher value of spin-only magnetic moment.

The correct order of spin-only magnetic moments is $$[MnCl_4]^{2-} > [CoCl_4]^{2-} > [NiCl_4]^{2-} > [ZnCl_4]^{2-}$$.

In these complexes, the central metal ion is in $$\displaystyle +2$$ oxidation state.

$$\displaystyle Zn^{2+}$$ has $$\displaystyle 3d^{10}$$ outer electronic configuration with $$\displaystyle 0$$ unpaired electrons.

$$\displaystyle Ni^{2+}$$ has $$\displaystyle 3d^{8}$$ outer electronic configuration with $$\displaystyle 2$$ unpaired electrons.

$$\displaystyle Co^{2+}$$ has $$\displaystyle 3d^{7}$$ outer electronic configuration with $$\displaystyle 3$$ unpaired electrons.

$$\displaystyle Mn^{2+}$$ has $$\displaystyle 3d^{5}$$ outer electronic configuration with $$\displaystyle 5$$ unpaired electrons.

Hence, the correct option is D.


SIMILAR QUESTIONS

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