Single Choice

The correct order of the spin-only magnetic moment of metal ions in the following low spin complexes, $$[V(CN)_6]^{4-}, [Fe(CN)_6]^{4-}$$, $$[Ru(NH_3)_6]^{3+}, $$ and $$[Cr(NH)_3)_6]^{2+}$$, is:

A$$V^{2+} > Cr^{2+} > Ru^{3+} > Fe^{2+}$$
Correct Answer
B$$V^{2+} > Ru^{3+} > Cr^{2+} > Fe^{2+}$$
C$$Cr^{2+} > V^{2+} > Ru^{3+} > Fe^{2+}$$
D$$Cr^{2+} > Ru^{3+} > Fe^{2+} > V^{2+}$$

Solution

Solution:- (A) $$V^{2+} > Cr^{2+} > Ru^{3+} > Fe^{2+}$$

According to equations, all the complexes are low spin.
Complex Configuration No. of
unpaired
electrons
$$[V(CN)_6]^{4-}$$ $$t_{2g} ^3e_g^0$$ 3

$$[Cr(NH)_3)_6]^{2+}$$
$$t_{2g} ^4e_g^0$$
2

$$[Ru(NH_3)_6]^{3+} $$
$$t_{2g} ^5e_g^0$$
1

$$[Fe(CN)_6]^{4-}$$

$$t_{2g} ^6e_g^0$$ 0


SIMILAR QUESTIONS

d - block and f - block Elements

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d - block and f - block Elements

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