Select the correct statement about carbonium ion, $$\overset{\oplus}{C}H_5$$
The bonding electron pairs in the $${ H }_{ 2 }$$ molecule is shared between the 2 hydrogen and 1 carbon atom. (3 center-2-electrons Bond) there are no empty orbitals It is not electron\deficient.
Arrange the carbanions, $$(\mathrm{C}\mathrm{H}_3)_{3}\overline{\mathrm{C}},\overline{\mathrm{C}}\mathrm{C}l_{3},(\mathrm{C}\mathrm{H}_3)_{2}\overline{\mathrm{C}}\mathrm{H},\ \mathrm{C}{}_{6}\mathrm{H}_{5}\overline{\mathrm{C}}\mathrm{H}_{2}$$ , in order of their decreasing stability:
Which one of the following substituents at para-position is most effective in stabilizing the phenoxide ion?
The false statements among the following are: I. A primary carbocation is less stable than a tertiary carbocation. II. A cyclopropyl methyl carbocation is less stable than allyl carbocation. III. A tertiary free radical is more stable than a primary free radical. IV. Isopropyl carbanion is more stable than ethyl carbanion.
Which of the following statement is not true about carbanions?
Which of the following is cabanion expected to be most stable?
The order of decreasing stability of the following carbanion is: (i) $${ (C{ H }_{ 3 }) }_{ 3 }C^- $$ (ii) $$C{ { H }_{ 3 } } ^-$$ (iii) $${ C{ H }_{ 3 } }C { }{ { H }_{ 2 } } ^-$$ (iv) $${ (C{ H }_{ 3 }) }_{ 2 }C{ H } ^-$$
Arrange the following carbanions in order of their decreasing stability. (I) $$H_3C-C\equiv C^-$$ (II) $$ H-C \equiv C^-$$ (III) $$ H_3C-CH^-_2$$
Give the order of stabilities of the following : a. $$ Ph_3 \dot {C} $$ b. $$ Ph \dot{ C}H_2 $$ c. $$ Me_3 \dot {C} $$ d. $$ \dot {C_2}H_5 $$ e. $$ \dot {CH_3} $$
Give the order of stabilities of the following : b. Ph3C⊖ c.Me2CH⊖ d.C⊖H3 e.C ⊖ 2 H5 f.Me3C⊖
The most stable carbanion is :