Single Choice

The order of decreasing stability of the following carbanion is: (i) $${ (C{ H }_{ 3 }) }_{ 3 }C^- $$ (ii) $$C{ { H }_{ 3 } } ^-$$ (iii) $${ C{ H }_{ 3 } }C { }{ { H }_{ 2 } } ^-$$ (iv) $${ (C{ H }_{ 3 }) }_{ 2 }C{ H } ^-$$

A$$ i > ii > iii > iv$$
B$$ iv > iii > ii > i$$
C$$iv > i > ii >iii$$
Dnone of these
Correct Answer

Solution

The order of stability of carbanion is $$\Rightarrow$$
$$methyl>1°>2°>3°$$

Therefore the correct order of stability of given carbanions are $$\Rightarrow$$

$$ii>iii>iv>i \; (\because \text{ii and iii both are primary, iv is secondary anad i is tertiary})$$

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