Differential Equations
Assume that a spherical rain drop evaporates at a rate proportional to its surface area. If k is a positive constant then differential equation involving the rate of change of the radius of the rain drop is
The differential equation of all parabolas whose axis is y-axis is:
$$axis = y\ axis$$
vertex is $$(0, k)$$
Equation of parabola is
$$(x - 0)^{2} = 4a(y - k)$$
$$x^{2} = 4ay - 4ak$$
Differentiate w.r.t $$x$$
$$2x = 4a \dfrac {dy}{dx}$$
$$x = 2a \dfrac {dy}{dx}$$
$$\therefore \dfrac {1}{2a} = \dfrac {1}{x} \dfrac {dy}{dx}$$
Differentiate w.r.t $$x$$,
$$\dfrac {d}{dx} \left (\dfrac {1}{x} . \dfrac {dy}{dx}\right ) = \dfrac {d}{dx} \left (\dfrac {1}{2a}\right )$$
$$\dfrac {1}{x} . \dfrac {d^{2}y}{dx^{2}} + \dfrac {dy}{dx} \left (-\dfrac {1}{x^{2}}\right ) = 0$$
$$\therefore x \dfrac {d^{2}y}{dx^{2}} - \dfrac {dy}{dx} = 0$$
Assume that a spherical rain drop evaporates at a rate proportional to its surface area. If k is a positive constant then differential equation involving the rate of change of the radius of the rain drop is
The differential equation of all parabolas whose axes are parallel to $$\mathrm{y}$$ -axis is:
$$\displaystyle \left ( x^{3}-y^{3} \right )dx+xy^{2}dy= 0.$$ Solving this we get $$\displaystyle \frac{k}{x}=e^{y^{m}/nx^{r}} $$.Find $$m+n+r$$ ?
If $$y=e^{m sin^{-1}x}$$, then show that $$(1-x^2)\dfrac{d^2y}{dx^2}-x\dfrac{dy}{dx}-m^2y=0$$.
If $$\displaystyle 2x=y^{\tfrac{1}{5}}+y^{-\tfrac{1}{5}}$$ and $$\displaystyle (x^2-1)\dfrac{d^2y}{dx^2}+\lambda x\dfrac{dy}{dx}+ky=0$$, then $$\lambda +k$$ is equal to:
Let $$(x,y,z)$$ be points with integer coordinates satisfying the system of homogeneous equations: $$3x-y-z=0$$ $$-3x+z=0$$ $$-3x+2y+z=0$$. Then the number of such points which lie inside a sphere of radius $$10$$ centered at the origin is
The differential equation of the family of circles touching y-axis at the origin is:
If $$ y={ \left( \tan ^{ -1 }{ x } \right) }^{ 2 }$$, then $${ \left( { x }^{ 2 }+1 \right) }^{ 2 }\cfrac { { d }^{ 2 }y }{ d{ x }^{ 2 } } +2x\left( { x }^{ 2 }+1 \right) \cfrac { dy }{ dx } =$$
if $$y = A{e^{ - kt}}\cos (pt + c)$$ , then prove that $${{{d^2}y} \over {d{t^2}}} + 2k{{dy} \over {dt}} + {n^2}y = 0$$ , where $${n^2} = {p^2} + {k^2}$$
Find the differential equation of all the parabola having axis parallel to the $$x-$$axis.