Single Choice

The ionization energy of boron is less than that of beryllium because:

Aberyllium has a higher nuclear charge that boron
Correct Answer
Bberyllium has a lower nuclear charge than boron
Cthe outermost electron in boron occupies a $$2p-$$orbital
Dthe $$2s$$ and $$2p$$-orbitals of boron are degenerate

Solution

$$B = 5:\ 1s^22s^22p^1$$
$$Be = 4: \ 1s^22s^2$$
As we can see from the electronic configuration of $$Be$$ it is having completely filled outermost shell which is highly stable whereas in $$B$$ outermost shell consists of one electron which can be removed easily for attaining a stable configuration. Hence ionization energy of B is greater than the ionization energy of $$Be$$.


SIMILAR QUESTIONS

Periodic Classification of Elements

Green house effect is caused by :

Periodic Classification of Elements

Ionization energy of gaseous $$Na$$ atoms is $$495.5$$ kJ mol$$^{-1}$$. The lowest possible frequency of light that ionizes a sodium atom is: $$[h=6.626\times 10^{-34} \ Js, N_A=6.022\times 10^{23} \ mol^{-1}]$$

Periodic Classification of Elements

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Periodic Classification of Elements

Ionizing radiation is:

Periodic Classification of Elements

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Periodic Classification of Elements

Would you expect the first ionization enthalpies for two isotopes of the same element to be the same or different? Justify your answer.

Periodic Classification of Elements

Which of the following can most easily form unipositive gaseous ion?

Periodic Classification of Elements

Beryllium has higher ionization enthalpy than boron. This can be explained as :

Periodic Classification of Elements

Ionization enthalpies of transition metals are:

Periodic Classification of Elements

The electronic states $$X$$ and $$Y$$ of an atom are depeicted below: $$X : 1s^{2} 2s^{2} 2p^{6} 3s^{1}$$ $$Y: 1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6} 4s^{1}$$ Which of the following statements is not correct?

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