Chemical Bonding
Which of the following arrangements represents the increasing order (smallest to largest) of ionic radii of the given species $$O^{2-}, S^{2-}, N^{3-}, P^{3-}$$?
What do you understand by isoelectronic species? Name a species that will be isoelectronic with each of the following atoms or ions. (i) F$$\displaystyle ^{-}$$ (ii) Ar (iii) Mg$$\displaystyle ^{2+}$$ (iii) Rb$$\displaystyle ^{+}$$
Isoelectronic species contain same number of electrons.
(i) Both $$\displaystyle F^-$$ and $$\displaystyle O^{2-} $$ contain 10 electrons each. Hence, they are isolectronic.
(ii) Both $$\displaystyle Ar $$ and $$\displaystyle Cl^- $$ contains 18 electrons each. Hence, they are isoelectronic.
(iii) Both $$\displaystyle Mg^{2+} $$ and $$\displaystyle Na^+ $$ contain 10 electrons each. Hence, they are isoelectronic.
(iv) Both $$\displaystyle Rb^+ $$ and $$\displaystyle Kr $$ contain 36 electrons. Hence, they are isoelectronic.
Which of the following arrangements represents the increasing order (smallest to largest) of ionic radii of the given species $$O^{2-}, S^{2-}, N^{3-}, P^{3-}$$?
The ionic radii (in $$\mathring{A}$$) of $$N^{3-}$$, $$O^{2-}$$ and $$F^{-}$$ are respectively :
The increasing order of the ionic radii of the given isoelectronic species is:
Which has the smallest size?
The correct order of decreasing ionic radius among the following anions would be:
Which of the following have the largest ionic size?
The species $$Ar, K^+$$ and $$Ca^{2+}$$ contain the same number of electrons. In which order do their radii increase?
The size of isoelectronic species $$F\displaystyle ^{-}$$, $$Ne$$ and $$Na\displaystyle ^{+}$$ is affected by :
$$K^{+}$$ and $$Cl^{-}$$ ions are isoelectronic. Which of the following statements is not correct?
Which one of the following groups represents a collection of isoelectronic species? (At. nos.: Cs-55, Br-35)