Chemical Bonding
The ionic radii (in $$\mathring{A}$$) of $$N^{3-}$$, $$O^{2-}$$ and $$F^{-}$$ are respectively :
Which of the following arrangements represents the increasing order (smallest to largest) of ionic radii of the given species $$O^{2-}, S^{2-}, N^{3-}, P^{3-}$$?
The correct order representing the increasing trend (smallest to largest) of ionic radii of the given species is $$O^{2-}$$. Since, Sulphur and Phosphorus belongs to 3rd period, their size will be larger than those who belongs to 2nd period like Nitrogen and Oxygen. While comparing the size of $$P^{3-}$$ and $$S^{2-}$$, first we will compare the size of Sulphur and Phosphorus, the size of Phosphorus is greater than Sulphur as the inter nuclear charge increases as we go from left to right in periodic table. On increasing charge, the repulsion increases and hence, the size. The more charge on the atom more will be the atomic radii.
The ionic radii (in $$\mathring{A}$$) of $$N^{3-}$$, $$O^{2-}$$ and $$F^{-}$$ are respectively :
The increasing order of the ionic radii of the given isoelectronic species is:
Which has the smallest size?
The correct order of decreasing ionic radius among the following anions would be:
Which of the following have the largest ionic size?
The species $$Ar, K^+$$ and $$Ca^{2+}$$ contain the same number of electrons. In which order do their radii increase?
What do you understand by isoelectronic species? Name a species that will be isoelectronic with each of the following atoms or ions. (i) F$$\displaystyle ^{-}$$ (ii) Ar (iii) Mg$$\displaystyle ^{2+}$$ (iii) Rb$$\displaystyle ^{+}$$
The size of isoelectronic species $$F\displaystyle ^{-}$$, $$Ne$$ and $$Na\displaystyle ^{+}$$ is affected by :
$$K^{+}$$ and $$Cl^{-}$$ ions are isoelectronic. Which of the following statements is not correct?
Which one of the following groups represents a collection of isoelectronic species? (At. nos.: Cs-55, Br-35)