Chemical Bonding
Which of the following arrangements represents the increasing order (smallest to largest) of ionic radii of the given species $$O^{2-}, S^{2-}, N^{3-}, P^{3-}$$?
Which of the following have the largest ionic size?
All species are isoelectronic. They have 10 electrons.
$$\displaystyle O^{2-}$$ has a least nuclear charge ( due to lowest atomic number) and hence has the largest ionic size as few positive charges are attracting more negative charges.
The correct order of ionic size:
$$O^{2-} > F^- > Na^+ > Mg^{2+}$$
Hence, option B is correct.
Which of the following arrangements represents the increasing order (smallest to largest) of ionic radii of the given species $$O^{2-}, S^{2-}, N^{3-}, P^{3-}$$?
The ionic radii (in $$\mathring{A}$$) of $$N^{3-}$$, $$O^{2-}$$ and $$F^{-}$$ are respectively :
The increasing order of the ionic radii of the given isoelectronic species is:
Which has the smallest size?
The correct order of decreasing ionic radius among the following anions would be:
The species $$Ar, K^+$$ and $$Ca^{2+}$$ contain the same number of electrons. In which order do their radii increase?
What do you understand by isoelectronic species? Name a species that will be isoelectronic with each of the following atoms or ions. (i) F$$\displaystyle ^{-}$$ (ii) Ar (iii) Mg$$\displaystyle ^{2+}$$ (iii) Rb$$\displaystyle ^{+}$$
The size of isoelectronic species $$F\displaystyle ^{-}$$, $$Ne$$ and $$Na\displaystyle ^{+}$$ is affected by :
$$K^{+}$$ and $$Cl^{-}$$ ions are isoelectronic. Which of the following statements is not correct?
Which one of the following groups represents a collection of isoelectronic species? (At. nos.: Cs-55, Br-35)