Single Choice

What is the oxidation number of iron in the compound $$ [Fe(H_2O)_5(NO)]SO_4 $$?

A$$ +2 $$
B$$ + 3$$
C$$ + 1 $$
Correct Answer
D$$ + 4 $$

Solution

Applying the oxidation number rule in $$ [ Fe (H_2O)_5 (NO)]SO_4 $$

$$ H_2 O $$ is a neutral and $$NO$$ is in $$+1$$ oxidation state.

$$[ x + (0) \times 5 +1] +(-2)=0 $$

$$ x +0 -1 = 0 \Rightarrow x = +1 $$

Hence, the oxidation number of Fe is +1.

SIMILAR QUESTIONS

Coordination Compounds

Which of the following has longest $$C-O$$ bond length? (Free C-O bond length in $$CO$$ is $$1.128\overset {\circ}{A}$$.)

Coordination Compounds

Which of the following processes does not involve oxidation of iron?

Coordination Compounds

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Coordination Compounds

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Coordination Compounds

Consider the following complex : $$[Co(NH_{3})_{5}CO_{3}]ClO_{4}$$ The coordination number, oxidation number, no. of $$d-electrons$$ and number of unpaired $$d-electrons$$ on the metal are respectively

Coordination Compounds

What is the oxidation number of $$Fe$$ in $$[Fe(H_{2}O)_{5}(NO)]^{2+}$$ ion?

Coordination Compounds

Which compound is zero valent metal complex?

Coordination Compounds

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Coordination Compounds

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Coordination Compounds

The pair of compounds in which metals are in the highest possible oxidation state is

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