Single Choice

Among the electrolytes $$Na_2SO_4,\: CaCl_2,\:Al_2(SO_4)_3$$ and $$NH_4Cl,$$ the most effective coagulating agent for $$Sb_2S_3$$ solution is:

A$$Na_2SO_4$$
B$$CaCl_2$$
C$$Al_2(SO_4)_3$$
Correct Answer
D$$NH_4Cl$$

Solution

$$Sb_{2}S_{3}$$ is a negative sol. So, $$Al_{2}(SO_{4})_{3}$$ will be the most effective coagulant due to higher charge density on $$Al^{3+}$$ in accordance with Hardy-Schulze rule. According to Hardy-Schulze rule, greater the valency of active ion, greater will be its coagulating power. Thus, Hardy-Schulze rule states the following: i. The ions carrying the charge opposite to that of sol particles are effective in causing coagulation of the sol. ii. The coagulating power of an electrolyte is directly proportional to the valency of the active ions (ions causing coagulation). Order of effectiveness of cations is as follows: $$Al^{3+}>Ca^{2+}>Na^{+}>NH_{4}^{+}$$

SIMILAR QUESTIONS

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