Single Choice

In Hardy-Weinberg equation, the frequency of heterozygous individual is represented by

Apq
B$$q^2$$
C$$p^2$$
D$$2$$pq
Correct Answer

Solution

Hardy-Weinberg equation is $$p^2$$ + 2pq + $$q^2$$ = 1. Here, p is the frequency of the "A" allele and q is the frequency of the "a" allele in the population. Thus, $$p^2$$ represents the frequency of the homozygous genotype AA, $$q^2$$ is the frequency of the homozygous genotype aa, and 2pq represents the frequency of the heterozygous genotype Aa.

SIMILAR QUESTIONS

Surface Chemistry

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Surface Chemistry

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Surface Chemistry

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Surface Chemistry

As per Hardy-Schulze formulation, the flocculation value of the following for ferric hydroxide sol are in the order :

Surface Chemistry

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Surface Chemistry

Which of the following will be the most effective in the coagulation of $$Fe(OH)_3$$ sol?

Surface Chemistry

Which of the following is most effective electrolyte in the coagulation of $$AgI/ Ag^{+}$$ sol? $$K_{2}SO_{4}, MgCl_{2}, K_{4}[Fe(CN)_{6}]$$.

Surface Chemistry

Which one of the following electrolytes is the most effective for the coagulation of $$Fe(OH)_{3}$$ sol and why? $$NaCl, Na_{2}SO_{4}, Na_{3}PO_{4}$$.

Surface Chemistry

Answer the following questions. Out of $$MgCl_{2}$$ and $$AlCl_{3}$$, which one is more effective in causing coagulation of negative charged sol and why?

Surface Chemistry

Answer the following question. Out of $$H_{2}SO_{4}$$ and $$H_{3}PO_{4}$$, which one is more effective in causing coagulation of positively charged sol? Give reason.

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