Surface Chemistry
The coagulating power of electrolytes having ions $$Na^{+},\ Al^{3+}$$ and $$Ba^{2+}$$ for arsenic sulphide sol increases in the order:
Which of the following will be the most effective in the coagulation of $$Fe(OH)_3$$ sol?
$$Fe(OH)_3$$ sol is positively charged sol. It will be coagulated by negatively charged ions.
$$Mg_3(PO_4)_2$$ provides phosphate ions $$PO_4^{3-}$$ which have maximum negative charge among the given electrolytes.
Hence, $$Mg_3(PO_4)_2$$ will be the most effective in the coagulation of $$Fe(OH)_3$$ sol.
The coagulating power of electrolytes having ions $$Na^{+},\ Al^{3+}$$ and $$Ba^{2+}$$ for arsenic sulphide sol increases in the order:
Among the electrolytes $$Na_2SO_4,\: CaCl_2,\:Al_2(SO_4)_3$$ and $$NH_4Cl,$$ the most effective coagulating agent for $$Sb_2S_3$$ solution is:
A sol has positively charged colloidal particles. Which of the following solutions is required in the lowest concentration for coagulation?
As per Hardy-Schulze formulation, the flocculation value of the following for ferric hydroxide sol are in the order :
For coagulation of arsenious sulphide sol, which one of the following salt solution will be most effective?
In Hardy-Weinberg equation, the frequency of heterozygous individual is represented by
Which of the following is most effective electrolyte in the coagulation of $$AgI/ Ag^{+}$$ sol? $$K_{2}SO_{4}, MgCl_{2}, K_{4}[Fe(CN)_{6}]$$.
Which one of the following electrolytes is the most effective for the coagulation of $$Fe(OH)_{3}$$ sol and why? $$NaCl, Na_{2}SO_{4}, Na_{3}PO_{4}$$.
Answer the following questions. Out of $$MgCl_{2}$$ and $$AlCl_{3}$$, which one is more effective in causing coagulation of negative charged sol and why?
Answer the following question. Out of $$H_{2}SO_{4}$$ and $$H_{3}PO_{4}$$, which one is more effective in causing coagulation of positively charged sol? Give reason.