Periodic Classification of Elements
Which sequence of ionization potential is correct?
Arrange the elements $$Se, Cl$$ and $$S$$ in the increasing order of ionisation energy.
Ionisation energy is the energy required to remove one electron from a neutral atom of an element. $$S$$ and $$Se$$ belong to VIA group elements. Down the group ionisation energy decreases so $$S$$ is having more IE value than $$Se.$$
$$S$$ and $$Cl$$ are the elements of the same period the IE value increases from left to right. So, $$Cl$$ is having more IE value than $$S$$.
So the correct order of IP is $$Se
Hence option $$B$$ is correct.
Which sequence of ionization potential is correct?
Which ionisation potential (IP) in the following equations involves the greatest ammount of energy?
Ionisation energy in the alkali metals group :
As nuclear charge increases and atomic radii increases, ionisation potential :
B has a smaller first ionization enthalpy than Be. Consider the following statements: (I) it is easier to remove $$2p$$ electron than $$2s$$ electron (II) $$2p$$ electron of B is more shielded from the nucleus by the inner core of electrons than the $$2s$$ electrons of Be (III) $$2s$$ electron has some penetration power than $$2p$$ electron (IV) atomic radius of B is more than Be (atomic number $$B=5, Be=4$$) The correct statements are:
In comparison to boron, berylium has:
The electronic configuration with the highest ionization enthalpy is:
Which of the following atoms has the highest first ionization energy?
The decreasing order of the ionization potential of the following elements is:
Which of the following has maximum ionisation potential?