Periodic Classification of Elements
Which sequence of ionization potential is correct?
Which of the following has maximum ionisation potential?
As we go down in a group, the ionisation energy decreases.
As we move along the period the ionisation energy increases.
This fact is based on effective nuclear charge.
More the effective nuclear charge, more will be ionisation energy.
Effective nuclear charge is inversely proportional to size of atom and directly proportional to nuclear charge.
So, due to smallest size Be has maximum ionisation energy.
Therefore, order of ionisation energy is as follows:
$$K < Na < Mg < Be$$
Which sequence of ionization potential is correct?
Which ionisation potential (IP) in the following equations involves the greatest ammount of energy?
Ionisation energy in the alkali metals group :
As nuclear charge increases and atomic radii increases, ionisation potential :
B has a smaller first ionization enthalpy than Be. Consider the following statements: (I) it is easier to remove $$2p$$ electron than $$2s$$ electron (II) $$2p$$ electron of B is more shielded from the nucleus by the inner core of electrons than the $$2s$$ electrons of Be (III) $$2s$$ electron has some penetration power than $$2p$$ electron (IV) atomic radius of B is more than Be (atomic number $$B=5, Be=4$$) The correct statements are:
In comparison to boron, berylium has:
The electronic configuration with the highest ionization enthalpy is:
Which of the following atoms has the highest first ionization energy?
The decreasing order of the ionization potential of the following elements is:
Arrange the elements $$Se, Cl$$ and $$S$$ in the increasing order of ionisation energy.