Single Choice

The decreasing order of the ionization potential of the following elements is:

A$$Ne> Cl> P> S> Al> Mg$$
B$$Ne> Cl> P> S> Mg> Al$$
Correct Answer
C$$Ne> Cl> S> P> Mg> Al$$
D$$Ne> Cl>S> P> Al> Mg$$

Solution

The decreasing order of the ionization potential of the following elements is $$Ne> Cl> P> S> Mg> Al$$.

In a period, on moving from left to right, ionisation enthalpy increases. In a group, on moving from top to bottom, the ionisation energy decreases.
Closed shell $$(Ne)$$, half-filled ($$P$$) and completely filled configuration ($$Mg$$) are the cause of the higher value of I.E.

Since octet is complete in $$Ne$$, a huge amount of energy is required to remove an electron as it will lead to disruption of stable electronic configuration. P has higher ionisation energy than S as P has a half-filled 3p subshell. Removal of an electron from P atom will break the stability of half-filled subshell.

Mg has higher ionisation energy than Al as Mg has completely filled 3s subshell. Removal of an electron from the Mg atom will break the stability of completely filled subshell. Also, less amount of energy is required to remove an electron from p-subshell than from s-subshell.

The outer electronic configurations of Mg and Al are $$ \displaystyle 3s^2$$ and $$ \displaystyle 3s^23p^1$$ respectively.

SIMILAR QUESTIONS

Periodic Classification of Elements

Which sequence of ionization potential is correct?

Periodic Classification of Elements

Which ionisation potential (IP) in the following equations involves the greatest ammount of energy?

Periodic Classification of Elements

Ionisation energy in the alkali metals group :

Periodic Classification of Elements

As nuclear charge increases and atomic radii increases, ionisation potential :

Periodic Classification of Elements

B has a smaller first ionization enthalpy than Be. Consider the following statements: (I) it is easier to remove $$2p$$ electron than $$2s$$ electron (II) $$2p$$ electron of B is more shielded from the nucleus by the inner core of electrons than the $$2s$$ electrons of Be (III) $$2s$$ electron has some penetration power than $$2p$$ electron (IV) atomic radius of B is more than Be (atomic number $$B=5, Be=4$$) The correct statements are:

Periodic Classification of Elements

In comparison to boron, berylium has:

Periodic Classification of Elements

The electronic configuration with the highest ionization enthalpy is:

Periodic Classification of Elements

Which of the following atoms has the highest first ionization energy?

Periodic Classification of Elements

Arrange the elements $$Se, Cl$$ and $$S$$ in the increasing order of ionisation energy.

Periodic Classification of Elements

Which of the following has maximum ionisation potential?

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