Subjective Type

At $$143\ K$$, the reaction of $$XeF_{4}$$ with $$O_{2}F_{2}$$ produces a xenon compound $$Y$$. The total number of lone pair(s) electrons present on the whole molecule of $$Y$$ is _________.

Solution

$$XeF_{4} + O_{2}F_{2} \rightarrow \underset {(Y)}{XeF_{6}} + O_{2}$$.

$$XeF_6$$ contains $$3\ lp$$ on each $$F$$ and $$1\ lp$$ on $$Xe$$.

Therefore, total number of lone pairs in molecule Y $$= 3\times 6 + 1 = 19$$

SIMILAR QUESTIONS

p - block Elements

Which forms maximum compounds with Xenon?

p - block Elements

$$XeF_2$$ on hydrolysis gives:

p - block Elements

$$XeF_6$$ on complete hydrolysis gives :

p - block Elements

Xenon hexafluoride on partial hydrolysis produces compounds 'X' and 'Y'. Compounds 'X' and 'Y' and the oxidation state of Xe are respectively _______.

p - block Elements

$$XeF_6$$ on partial hydrolysis with water produces a compound $$X$$. The same compound $$X$$ is formed when $$XeF_6$$ reacts with silica. The compound $$X$$ is:

p - block Elements

Which of the following fluorides of xenon is impossible?

p - block Elements

$$Xe{F}_{4}$$ disproportionate in water to give:

p - block Elements

Which one of the following reactions of xenon compounds is not feasible?

p - block Elements

Which combination gives the maximum number of products?

p - block Elements

Which of the following Xenon compound does not produce explosive $$XeO_3$$ on its complete hydrolysis?

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