Single Choice

Xenon hexafluoride on partial hydrolysis produces compounds 'X' and 'Y'. Compounds 'X' and 'Y' and the oxidation state of Xe are respectively _______.

A$$XeOF_4(+6)$$ and $$XeO_2F_2(+6)$$
Correct Answer
B$$XeOF_4(+6)$$ and $$XeO_3(+6)$$
C$$XeO_2F_2(+6)$$ and $$XeO_2(+4)$$
D$$XeO_2(+4)$$ and $$XeO_3(+6)$$

Solution

Xenon hexafluoride on partial hydrolysis produces compounds $$XeOF_4 $$ and $$XeO_2F_2 $$. In the compounds $$XeOF_4 $$ and $$XeO_2F_2 $$, the oxidation states of Xe are $$+6$$ and $$+6$$ respectively.
$$XeF_6 + H_2O \rightarrow XeOF_4 + 2 HF$$
$$ XeOF_4 + H_2O \rightarrow XeO_2F_2 + 2 HF$$

SIMILAR QUESTIONS

p - block Elements

Which forms maximum compounds with Xenon?

p - block Elements

$$XeF_2$$ on hydrolysis gives:

p - block Elements

$$XeF_6$$ on complete hydrolysis gives :

p - block Elements

$$XeF_6$$ on partial hydrolysis with water produces a compound $$X$$. The same compound $$X$$ is formed when $$XeF_6$$ reacts with silica. The compound $$X$$ is:

p - block Elements

Which of the following fluorides of xenon is impossible?

p - block Elements

At $$143\ K$$, the reaction of $$XeF_{4}$$ with $$O_{2}F_{2}$$ produces a xenon compound $$Y$$. The total number of lone pair(s) electrons present on the whole molecule of $$Y$$ is _________.

p - block Elements

$$Xe{F}_{4}$$ disproportionate in water to give:

p - block Elements

Which one of the following reactions of xenon compounds is not feasible?

p - block Elements

Which combination gives the maximum number of products?

p - block Elements

Which of the following Xenon compound does not produce explosive $$XeO_3$$ on its complete hydrolysis?

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