p - block Elements
Which forms maximum compounds with Xenon?
Which combination gives the maximum number of products?
The given reactions proceed as follows:
$$P_4 + SOCl_2 \rightarrow PCl_3 + SO_2 + S_2Cl_2$$
Total no. of products = 3
$$P_4 + SO_2Cl_2 \rightarrow PCl_5 + SO_2$$
Total no. of products = 2
$$XeF_4 + H_2O \rightarrow XeO_3 + Xe + O_2 + HF$$
Total no. of products = 4
$$NH_4NO_3 + (excess )NaOH \rightarrow NaNO_3 + NH_3 + H_2O$$
Total no. of products = 3
Hence, option C is correct.
Which forms maximum compounds with Xenon?
$$XeF_2$$ on hydrolysis gives:
$$XeF_6$$ on complete hydrolysis gives :
Xenon hexafluoride on partial hydrolysis produces compounds 'X' and 'Y'. Compounds 'X' and 'Y' and the oxidation state of Xe are respectively _______.
$$XeF_6$$ on partial hydrolysis with water produces a compound $$X$$. The same compound $$X$$ is formed when $$XeF_6$$ reacts with silica. The compound $$X$$ is:
Which of the following fluorides of xenon is impossible?
At $$143\ K$$, the reaction of $$XeF_{4}$$ with $$O_{2}F_{2}$$ produces a xenon compound $$Y$$. The total number of lone pair(s) electrons present on the whole molecule of $$Y$$ is _________.
$$Xe{F}_{4}$$ disproportionate in water to give:
Which one of the following reactions of xenon compounds is not feasible?
Which of the following Xenon compound does not produce explosive $$XeO_3$$ on its complete hydrolysis?