Single Choice

Which of the following fluorides of xenon is impossible?

A$$Xe{ F }_{ 2 }$$
B$$Xe{ F }_{ 3 }$$
Correct Answer
CXeF4
DXeF6

Solution

Xenon is an inert gas. Its electronic configuration is $$ \displaystyle [Kr]
4d^{10} 5s^2 5p^6$$.
All orbitals that are filled have paired electrons.

When one, two or three electrons are promoted from 5p (filled) to 5d (empty) orbitals, two, four and six half-filled orbitals are formed.

Xenon can combine with even number of F atoms to form $$ \displaystyle XeF_2$$, $$ \displaystyle XeF_4$$ or $$ \displaystyle XeF_6$$. It cannot combine with odd number of F atoms.

Thus, formation of $$ \displaystyle XeF_3$$ and $$ \displaystyle XeF_5$$ is not possible.

SIMILAR QUESTIONS

p - block Elements

Which forms maximum compounds with Xenon?

p - block Elements

$$XeF_2$$ on hydrolysis gives:

p - block Elements

$$XeF_6$$ on complete hydrolysis gives :

p - block Elements

Xenon hexafluoride on partial hydrolysis produces compounds 'X' and 'Y'. Compounds 'X' and 'Y' and the oxidation state of Xe are respectively _______.

p - block Elements

$$XeF_6$$ on partial hydrolysis with water produces a compound $$X$$. The same compound $$X$$ is formed when $$XeF_6$$ reacts with silica. The compound $$X$$ is:

p - block Elements

At $$143\ K$$, the reaction of $$XeF_{4}$$ with $$O_{2}F_{2}$$ produces a xenon compound $$Y$$. The total number of lone pair(s) electrons present on the whole molecule of $$Y$$ is _________.

p - block Elements

$$Xe{F}_{4}$$ disproportionate in water to give:

p - block Elements

Which one of the following reactions of xenon compounds is not feasible?

p - block Elements

Which combination gives the maximum number of products?

p - block Elements

Which of the following Xenon compound does not produce explosive $$XeO_3$$ on its complete hydrolysis?

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