Single Choice

$$BF_{3}$$ forms an adduct with $$NH_{3}$$ because:

Anitrogen has high electronegativity
Bboron has high electronegativity
Cboron has an empty p-orbital and nitrogen has lone pair of electrons
Correct Answer
Dboron has electro positive nature

Solution

$$BF_3$$ forms adduct with $$NH_3$$ because of the dative bond formed between $$BF_3$$ and $$NH_3$$.

SIMILAR QUESTIONS

Chemical Bonding

PF$$_{3}$$ can act as a donor molecule while NF$$_{3}$$ shows little tendency to act as a donor. This is because in PF$$_{3}$$, lone-pair on P is easily donated compared to that of N.

Chemical Bonding

Which of the following can act as Lewis acid?

Chemical Bonding

Which of the following molecule is not hypovalent

Chemical Bonding

Which of the following does not contain any coordinate bond?

Chemical Bonding

Which one of the following does not have a pyramidal shape?

Chemical Bonding

Which of the following does not contain any coordinate bond?

Chemical Bonding

Explain the following on the basis of valence bond theory: $$BF_{3}$$ is planar but $$NH_{3}$$ is not.

Chemical Bonding

$$BF_3$$ has less lewis acidic property than $$BBr_3$$ . Why ?

Chemical Bonding

$$(CH_3)_3$$ COH is less acid than $$(CH_3)_3$$ SiOH. Why ?

Chemical Bonding

In co-ordinate bonds, the acceptor atoms must essentially contain in its valency shell an orbitial:

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