Subjective Type

Explain the following on the basis of valence bond theory: $$BF_{3}$$ is planar but $$NH_{3}$$ is not.

Solution

In $$BF_{3}, B$$-atom undergoes $$sp^{2}$$ hybridisation. Hence $$BF_{3}$$ is triangular planar. In $$NH_{3},N$$-atom undergoes $$sp^{3}$$ hybridisation. Hence $$NH_{3}$$ has pyramidal shape with one lone pair on N-atom.

SIMILAR QUESTIONS

Chemical Bonding

$$BF_{3}$$ forms an adduct with $$NH_{3}$$ because:

Chemical Bonding

PF$$_{3}$$ can act as a donor molecule while NF$$_{3}$$ shows little tendency to act as a donor. This is because in PF$$_{3}$$, lone-pair on P is easily donated compared to that of N.

Chemical Bonding

Which of the following can act as Lewis acid?

Chemical Bonding

Which of the following molecule is not hypovalent

Chemical Bonding

Which of the following does not contain any coordinate bond?

Chemical Bonding

Which one of the following does not have a pyramidal shape?

Chemical Bonding

Which of the following does not contain any coordinate bond?

Chemical Bonding

$$BF_3$$ has less lewis acidic property than $$BBr_3$$ . Why ?

Chemical Bonding

$$(CH_3)_3$$ COH is less acid than $$(CH_3)_3$$ SiOH. Why ?

Chemical Bonding

In co-ordinate bonds, the acceptor atoms must essentially contain in its valency shell an orbitial:

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